6x^2+36x-246=0

Solution for 6x^2+36x-246=0 equation:

6x^2+36x-246=0

a = 6; b = 36; c = -246;
Δ = b2-4ac
Δ = 362-4·6·(-246)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60\sqrt{2}}{2*6}=\frac{-36-60\sqrt{2}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60\sqrt{2}}{2*6}=\frac{-36+60\sqrt{2}}{12}
$